A parking lot charges $3 to park a car for the first hour and $2 per hour after that. If you use more than one parking space, the second and each subsequent car will be charged 75% of what you pay to park just one car. If you park 3 cars for t hours, which function gives the total parking charge?A ) f(t) = 3(3 + 2(t − 1)) B ) f(t) = (3 + 2t) + 0.75 × 2(3 + 2t) C ) f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1)) D ) f(t) = (3 + 2t) + 0.75(3 + 2t) + 0.75 × 0.75(3 + 2t) E ) f(t) = (3 + 2(t − 1)) + 0.75(3 + 2(t − 1)) + 0.75 × 0.75(3 + 2(t − 1))Ps. I picked C

Given, a parking lot charges $3 for first hour and $2 per hour after that.So for t hours, the parking lot charges $3 for the first hour and after first hour there is [tex] (t-1) [/tex] hours left. So for [tex] (t-1) [/tex] hours it will charge $2 per hour.The charges for [tex] (t-1) [/tex] hours = $[tex] 2(t-1) [/tex].Total charges for t hours for one car = $[tex] (3+2(t-1)) [/tex]Now for the second car, it will charge 75% of the first car.So the charges for second car =$[ [tex] (3+2(t-1))(75/100) [/tex]]=$[tex] 0.75(3+2(t-1)) [/tex]There are 3 cars. That parking charges for the third car is also 75% of the first car.So for third car the parking charges are same as for the second car.Total parking charges for 3 cars= $[tex] (3+2(t-1))+(0.75(3+2(t-1))+(0.75(3+2(t-1)) [/tex]= $[tex] (3+2(t-1))+(0.75)(2(3+2(t-1)) [/tex]We have got the required answer here.The correct option is option C.